# Calculate the density of petroleum products

In order to determine with the help of this table, the density of the oil product at a given temperature, you should:

Density at 20 °С | Temperature correction of 1 °С | Density at 20 °С | Temperature correction of 1 °С |
---|---|---|---|

0.6500–0.6590 | 0.000962 | 0.8300–0.8399 | 0.000725 |

0.6600–0.6690 | 0.000949 | 0.8400–0.8499 | 0.000712 |

0.6700–0.6790 | 0.000936 | 0.8500–0.8599 | 0.000699 |

0.6800–0.6890 | 0.000925 | 0.8600–0.8699 | 0.000686 |

0.6900–0.6999 | 0.000910 | 0.8700–0.8799 | 0.000673 |

0.7000–0.7099 | 0.000897 | 0.8800–0.8899 | 0.000660 |

0.7100–0.7199 | 0.000884 | 0.8900–0.8999 | 0.000647 |

0.7200–0.7299 | 0.000870 | 0.9000–0.9099 | 0.000633 |

0.7300–0.7399 | 0.000857 | 0.9100–0.9199 | 0.000620 |

0.7400–0.7499 | 0.000844 | 0.9200–0.9299 | 0.000607 |

0.7500–0.7599 | 0.000831 | 0.9300–0.9399 | 0.000594 |

0.7600–0.7699 | 0.000818 | 0.9400–0.9499 | 0.000581 |

0.7700–0.7799 | 0.000805 | 0.9500–0.9599 | 0.000567 |

0.7800–0.7899 | 0.000792 | 0.9600–0.9699 | 0.000554 |

0.7900–0.7999 | 0.000778 | 0.9700–0.9799 | 0.000541 |

0.8000–0.8099 | 0.000765 | 0.9800–0.9899 | 0.000528 |

0.8100–0.8199 | 0.000752 | 0.9900–1.0000 | 0.000515 |

0.8200–0.8299 | 0.000738 |

- found on the passport of the density of petroleum at +20 °С;
- measure the average temperature in the cargo tank;
- determine the difference between +20 °C and an average temperature of the cargo;
- on a graph of the temperature correction to find the correction of 1 °C, corresponding to the density of the product at +20 °C;
- multiply the temperature correction to the density of the temperature difference;
- obtained in Section "d" work to subtract from the density at +20 °C, if the average temperature of the oil product in the tank is above +20 °C, or add this product if the product temperature below +20 °C.

## Example №1

The density of petroleum product at +20 °C, according to the passport 0.8240. The temperature of mineral oil in the tank +23 °C. Determine the density of mineral oil on the table at this temperature.

### We find:

- temperature difference of 23 °C − 20 °C = 3 °C;
- temperature correction of 1 °C on the table for the density of 0.8240, representing 0.000738;
- temperature correction of 3 °C: 0.000738 × 3 = 0.002214 or 0.0022 is rounded;
- required density of mineral oil at a temperature of +23 °C (amendment must be subtracted, as the temperature in the cargo tank above +20 °C), equal to 0.8240 − 0.0022 = 0.8218 or 0.8220 is rounded.

## Example №2

The density of petroleum at +20 °C, according to a passport, 0.7520. The temperature in the cargo tank −12 °C. Determine the density of petroleum product at this temperature.

### We find:

- the temperature difference between +20 °C − (−12 °C) = 32 °C;
- temperature correction of 1 °C on the table for the density of 0.7520, representing 0.000831;
- temperature correction to 32 °C, equal to 0.000831 × 32 = 0.026592 or 0.0266 is rounded;
- required density of mineral oil at a temperature of −12 °C (the amendment should be added, as the temperature of the load in the tank below +20 °C), equal to 0.7520 + 0.0266 = 0.7786 or 0.7785 is rounded.