# Calculate the density of petroleum products

In order to determine with the help of this table, the density of the oil product at a given temperature, you should:

Table of average temperature corrections of the density of petroleum products
Density at 20 °СTemperature correction of 1 °СDensity at 20 °СTemperature correction of 1 °С
0.6500–0.65900.0009620.8300–0.83990.000725
0.6600–0.66900.0009490.8400–0.84990.000712
0.6700–0.67900.0009360.8500–0.85990.000699
0.6800–0.68900.0009250.8600–0.86990.000686
0.6900–0.69990.0009100.8700–0.87990.000673
0.7000–0.70990.0008970.8800–0.88990.000660
0.7100–0.71990.0008840.8900–0.89990.000647
0.7200–0.72990.0008700.9000–0.90990.000633
0.7300–0.73990.0008570.9100–0.91990.000620
0.7400–0.74990.0008440.9200–0.92990.000607
0.7500–0.75990.0008310.9300–0.93990.000594
0.7600–0.76990.0008180.9400–0.94990.000581
0.7700–0.77990.0008050.9500–0.95990.000567
0.7800–0.78990.0007920.9600–0.96990.000554
0.7900–0.79990.0007780.9700–0.97990.000541
0.8000–0.80990.0007650.9800–0.98990.000528
0.8100–0.81990.0007520.9900–1.00000.000515
0.8200–0.82990.000738
1. found on the passport of the density of petroleum at +20 °С;
2. measure the average temperature in the cargo tank;
3. determine the difference between +20 °C and an average temperature of the cargo;
4. on a graph of the temperature correction to find the correction of 1 °C, corresponding to the density of the product at +20 °C;
5. multiply the temperature correction to the density of the temperature difference;
6. obtained in Section "d" work to subtract from the density at +20 °C, if the average temperature of the oil product in the tank is above +20 °C, or add this product if the product temperature below +20 °C.

## Example №1

The density of petroleum product at +20 °C, according to the passport 0.8240. The temperature of mineral oil in the tank +23 °C. Determine the density of mineral oil on the table at this temperature.

### We find:

1. temperature difference of 23 °C − 20 °C = 3 °C;
2. temperature correction of 1 °C on the table for the density of 0.8240, representing 0.000738;
3. temperature correction of 3 °C: 0.000738 × 3 = 0.002214 or 0.0022 is rounded;
4. required density of mineral oil at a temperature of +23 °C (amendment must be subtracted, as the temperature in the cargo tank above +20 °C), equal to 0.8240 − 0.0022 = 0.8218 or 0.8220 is rounded.

## Example №2

The density of petroleum at +20 °C, according to a passport, 0.7520. The temperature in the cargo tank −12 °C. Determine the density of petroleum product at this temperature.

### We find:

1. the temperature difference between +20 °C − (−12 °C) = 32 °C;
2. temperature correction of 1 °C on the table for the density of 0.7520, representing 0.000831;
3. temperature correction to 32 °C, equal to 0.000831 × 32 = 0.026592 or 0.0266 is rounded;
4. required density of mineral oil at a temperature of −12 °C (the amendment should be added, as the temperature of the load in the tank below +20 °C), equal to 0.7520 + 0.0266 = 0.7786 or 0.7785 is rounded.